Hahaha, you guys are WAY to nice!! I love you guys!! Well, I think it is "Time", I had that experience today, in study hall, I was done 20 minutes earlier, and it seemed like a lifetime!!! Haha, and between classes, you know what that's like!!

correct! your turn!

Whoo hoo!!!! It's worth it!! *Elvis Voice* Thank you, thank you very much! Haha!! I guess I had so much desperation that I answer the simplest riddle, and so much determintaion to get one wrong!! That should totally be a famous qoute!!! Okay, here's the toughest one, now wait, DO NOT LOOK UP ONLINE PLEASE!! It just ruins all the fun!! Here goes;

You are locked in a jail cell with no windows. and you need to tap out a message on the wall for the man in the other cell next to you. The problem is that you have to do it at exactly 9:15 PM, when the guard outside is switched, so your noise won't be noticed. You can't hear the switching of the guards through your walls, and you have no clock.

There is a faucet with water dripping very consistently from it in the corner, but you don't know if it is dripping at 30 or 40 or however many drops per minute, and that wouldn't give you the time in any case. You can just make out the chiming of a church bell, but it chimes just once at the top of each hour, so you can't tell the time from that. You can feel the wall facing west start to cool after the sun sets, but you don't know what time the sun is setting, and this isn't very precise in any case. Your dinner is always passed into your cell between 6:15 and 6:45. How do you determine when it is exactly 9:15 PM?

Haha, have fun!!

Good one rebel_megz!!!
hmmm...I knew one that is very simmilar, I'll try the same reasoning...
I guess it is some kind of sequence....guiding yourself by the sounds of the church bell right?, because it would be the only thing that gives you certainty of the hour.
First, you have to hear the church bell after your dinner is served, that would be at 7.00pm...when you hear the bell you should start counting the drops until you hear the next one (that would be 8:00pm); then you divide that number by 60 and then multiply it by 15 to get how many drops are in fifteen minutes...Finally, when you last hear the church bell, you'll know that it is 9.00 o'clock sharp, then you count the number of drops (the result of the division and the multiplication) and then you'll know when it is 9.15 pm...

That's the only logical answer I could come up with....I'll keep thinking in case there is some other...oops, I didn't use the sun setting....hmmm....

Hmm, that is right, but since you answered so fast, can you find another way??


I guess I didn't make myself clear with my post, let me clarify;

I looked through and the one you posted DOES work, and I didn't realize that there was going to be another way, and that is NOT the way I was thinking of! So, initially, that would be incorrect.

As for your question about the sun setting, I can't truthfully answer whether or not it would be part of the solution, since you found a sneaky way around the actual solution!'

I hope I make more sense now!

Well, the only thing that exactly tells you the hour is the chiming of the bell...
And the sunset it's quite irrelevant because the hour of that particular event changes depending on the season. The sun would tell him the hour if he could make a sun clock , otherwise...

Hmmm, I think that instead of dividing the number of drops by 60, he could divide them by 4, so he would have the number of drops that fall in 15 minutes.

I think you should just ask the guard to let you know when it's 9:15.

You got it right, Phoenix_1, so go ahead and post the next one.

Ok, here it goes....enjoy!!!

It's pretty hard, so I'll give a hint...use lateral thinking...

You are in a room that is completly blocked in on all six sides (including ceiling and floor). You just have a mirror and a wooden table in the room. How do you get out?

I don't normally answer ones I've heard before, but this one's the type of word play that I think would be nearly impossible to come up with without hearing it first or getting lots of hints.

So if I remember correctly you need to look in the mirror and see what you saw. Then you take the saw and saw the table in half. Two halves make make a whole (hole). Climb through the hole and you're out.

It is correct indeed, Albus-wan, congratulations!!!


now it's your turn

All right, I think we'll stick to one similar to the last one, so here we go:

You're in a room lit only by artificial light. The floor is made of concrete. In the center of the room is a cylindrical steel pipe sticking into the ground. The pipe is 25 cm in length. 15 cm of the pipe is below ground while 10 cm is above ground. The diameter of the pipe is just wide enough that a ping pong ball can slide to the bottom, and in fact there is a ping ball resting at the bottom of the pipe 15 cm below ground. Also in the room with you are a 30 cm piece of string, a 30 cm wooden ruler that is wider than a ping pong ball, a paper clip, a magnifying glass, and a simple pocket knife with a dull 4 cm blade. Without leaving the room and without damaging the ping pong ball, how do you get the ping pong ball out of the pipe?

Good luck!

The articles are useless in this case, and being no other form of liquid , the only way to get the ping pong ball out would be to urinate in the hole so the ball would float upwards!

I bet I'm wrong!

No, Elaine, I'm very sorry to tell you that you are incorrect--by which I mean you're answer is not wrong and you would lose your bet. There really is no other way to get the ping pong ball to the top. Now go wash that ping pong ball and when you get back you can give us the next riddle!

I must confess...I did already know the answer to that riddle, but being a family site, I assumed that no-one would post one with such an answer ....except you


What row of numbers comes next in this series?


1
11
21
1211
111221
312211
13112221

Well, it was a riddle I had posted on here long ago, but I thought no one who was currently participating had been around long enough to remember. For a while every time I got one right I would rack my brains trying to think of one that had not been posted. Now I just try and think of one that was posted a really long time ago.

Anyways, to the riddle at hand. I've got four answers and you can tell me if any is correct:

11111101111011
1000010010110100100100100011011
2120116011203120311011
11100111100111001111001111011

*crosses fingers*

hmmm I've seen this kind of riddles before, so I'll give it a try...

is it 1113213211??

three ones, one three, two ones, three twos, and two ones...never mind the written part...ohh I'm dizzy now....

I had a feeling that this riddle had been on here before! Phoenix_1, you are correct, the next line does in fact describe the previous one as you said.

You're up next......

Hey, what about me? You didn't say whether or not mine was right!

Hmm, next time I get a chance my riddle's going to be to explain how each of my four answers was right.

Anyways, Phoenix_1 got the nod, so let's see what you got.

Ok here it goes....enjoy!!!

there are five hats inside of a dark closet: three blue and two red.
Knowing this, three smart men go into the closet, and each selects a hat in the dark and places it unseen upon his head.
Once outside the closet, no man can see his own hat. The first man looks at the other two, thinks, and says, “I cannot tell what colour my hat is.” The second man hears this, looks at the other two, and says, “I cannot tell what colour my hat is either.” The third man is blind. The blind man says, “Well, I know what colour my hat is.” What colour is his hat?

It's easy

Hmm, let me see...

The first man sees a blue hat and a red hat
The second man sees a blue hat and another blue hat
The blind one suspects his is a red hat

Or something like that!

Hey, I think I'm right!

The blind man's hat is blue

Both the seeing men see one blue hat and one red hat, so they have no idea which one it could be on their own head.

Hope i got it!

Ima_LoOnYLoVeGoOd got the color of the hat right but the proof's not complete. Both of the other men's hats could also be blue, one could have a blue hat and the other a red one, or both of the other men could have red hats and it would still work.

The shortest proof that the blind man's hat is blue is if he assumes that it's red, in which case the other two men either both have blue hats or one has a blue hat and the other has a red hat. If one has a blue hat and the other has a red hat, then the one with the blue hat on would see two red hats and immediately know that his own hat was blue and it wouldn't matter which of them had the blue hat on since he wouldn't need additional information to figure out which color hat he had on.

Now, if both of the other men have blue hats on, then the first man would see that the blind man was wearing a red hat and the other man was wearing a blue hat, so he wouldn't know what color his own hat was; however, the second man would know that the blind man had a red hat on and that if he had a red hat on his own head then the first man would know that he (the first man) had a blue hat on, so he (the second man) would know that his own hat was blue based on the fact that the first man didn't know the color of his own hat.

Since the only scenarios where the blind man has a red hat on lead to one of the other men being able to guess the color of his own hat, the blind man knows that the hat on his own head is not red, therefore he can conclude that the hat on his own head is blue, assuming of course that there is a scenario under which the blind man has a blue hat on and the other two are not able to figure out which color hat they are wearing. Ima_LoOnYLoVeGoOd chose one of those scenarios, so the proof is complete, though it would be possible to show that the remaining scenarios where the blind man has a blue hat on would also work.

The first man doesn't know what colour hat he is wearing. He would only know what colour hat he was wearing if he could see that the other two men were both wearing red hats, as there were only two red hats in the cupboard. This is not the case so either:-

Man 2 and 3 are both wearing blue hats or,

one is wearing red and the other is wearing blue

When man 2 speaks I would assume he has thought of all of this. When 2 looks at 3 if 3 were wearing red then he would know that he must be wearing blue as they can't both be wearing red. But this does not happen so man 3 must be wearing blue, meaning that man 2 doesn't know if he is wearing red or blue:

The third man must be wearing a blue hat.

Now I am confused.....

You three guys got it right, but although Albus-wan answered after Ima_ LoOnYLoVeGoOd, he explained the answer properly. I'm sorry Loony.

Your turn Albus.

All right, I warned you all I was going to do it. Here we go.

Phoenix_1 gave the only completely right answer to the Elaine's riddle which was to provide the next line of the following sequence:

1
11
21
1211
111221
312211
13112221

The correct answer was 1113213211 (one 1 one 3 two 1s three 2s one 1). I gave four answers that were loosely based on Phoenix_1's correct answer. They were:

11111101111011
1000010010110100100100100011011
2120116011203120311011
11100111100111001111001111011

How did I choose those answers?

I have one hint that I'll provide if the first person to answer does not give the correct answer for all four of the numbers. Good luck!

I came up with one possibility for the first set of numbers....which does make sense taking the correct answer into account (1113213211)...even though I don't think this is what you thought I'll post it anyways:

I assumed that you counted the 2s as 0s; and you put 1 for each of the other numbers (the 1s and 3s) so it would be:

111+3 = 6 so 111111
2=0
1+3=4 so 1111
2=0
1+1= 2 so 11

if you put the results all toghether you'll get : 11111101111011

I seriously doubt that this reasoning is correct...anyways, that's the olny answer I could come up to for it.

I'm still working on the rest...

As promised, here's my hint. All four of the answers involve some conversion to binary. Your answer for the first one, Phoenix_1, was clever but incorrect. The answer should become clearer once you put on your binary glasses and your thinking cap.

Hmmm....
Ok so I'm trying to find the answers but I'm kind of having a headache right now....
It's a tough thing to do since I don't remember ever working with bynaries in my life.

If I come to at least one of the answers I'll let you now.

Now I see why Elaine said that you think too intelligently...

Just some basic binary conversion:

1 = 1
2 = 10
3 = 11
4 = 100
5 = 101
6 = 110
7 = 111
8 = 1000
9 = 1001

You might find this website useful. All four answers were just variations on a theme.

Ohh thank you very much!!!

So the first one would be....
1=1
1=1
1=1
3=11
2=10
1=1
3=11
2=10
1=1
1=1
-------------------
11111101111011



I tried working on the others but I couldn't get them, and I don't usually give up, but....you really like chopping logic....

All right, good enough. People have obviously lost interest in this riddle, so I'll turn it over to you Phoenix_1 to post the next riddle.

You got the first one right. Here's the explanation for the rest of them.

2. Take the correct answer, 1113213211, and convert it to binary and you get 1000010010110100100100100011011, or in other words 2^30 + 2^2\5 + 2^22 + 2^20 + 2^19 + 2^17 + 2^14 + 2^11 + 2^8 + 2^4 + 2^3 + 2^1 + 2^0 = 1113213211. I would be pretty impressed if someone took the time to do this by hand, but there are a number of converters readily available on the internet--including the one you linked to. If I was trying to figure this one out on my own I would have seen only 1s and 0s and thought to see what number came up if I converted from binary to decimal.

3. Take the previous number in the sequence, 13112221, and convert it to binary (using a conversion tool) which gives you 110010000001001110011101. Now describe this number as you did for the correct answer (two 1s two 0s one 1 six 0s and so on) and that gives you 2120116011203120311011.

4. Start off with the binary version of the previous sequence as in number 3, but this time describe it as you did in the correct answer but using binary numbers as in number 1 (10 1 10 0 1 1 110 0 and so on) which gives the final answer (actually it looks like I made a mistake originally).

So, like I said, go ahead and give us the next riddle, Phoenix_1.

Thanks Albus...
Well, I confess that I had worked on those numbers for some days, and the only thing I could come up with was turning them into binaries and then try to multiply them or either make some other mathematical operations, which now I realized I was far from what you originally thought....and taking into account that I've never used binaries before, I became discouraged at last...

That being said, here's my riddle enjoy!!

In a country, there are over 100 streets. Street 1 is named First Street, street 2 is named Second Street, and so on and so forth.

A traveller decides to walk through all these streets in the country. He could find all the streets except Street 62. No matter how hard he tried, he could not find it.

He later found that the locals had given the street another name.

What is the name?

Hmm...that seems like there are loads of ways, but my way is
1) Say it out loud "Sixty Second Street" or my point is, it would be called Minute Street. There are 60 Seconds in one minute, get it? That is a very very very clever one Pheonix_1, it took me awhile to figure it out! Genuis!

Ohh...you were the one who figured it out, no compliments for me...Congratulations!!!

Now it's your turn rebel_megz

Nonono, that was a good one! Funny story really, I was reading it to my sister out loud and instead of saying "Street 62" I said "62nd Street", that I started laughing! She stared at me like a crazy brunnette, which I am!

Here's mine;

A Mustang horse is tied to a five meter red rope in front of an old saloon after a party. Seven meters and 3 inches behind the horse is a bale of alfalfa hay. The horse's owner is male wearing a red shirt and had a couple beers, and so he is drunk. Not one single man or woman likes the owner or the horse. The owner stays two nights at the bar, completly forgeting his horse, no one speaks to the horse owner. Without breaking his red rope, the horse is able to eat the hay whenever he chooses. How is this possible?

Have fun!!

Uh oh... Don't know!

Lemme think about it...

OOH! The rope isn't tied to anything else! I just figured it out!

Nope, I'm afraid you're wrong No.1_HarryPotterFan although must I say that was a good guess!

well, let's assume that the rope is tied to a tree. The the rope is five meters long, which would give the horse a five meter radius, or a ten meter diameter. Also assuming that the hay is seven meters and 3 inches behind the horse when the horse is at least two meters and three inches away from the tree, it would follow that the horse could easily reach the hay while remaining tied to the tree.

You are to smart HP'sPrincessFiona! I'm afraid that isn't the right answer either! I'll give you one hint, no man or woman likes the owner - think about it...

The only two things that I could come up with are
1) Although they don't talk to the owner, someone might've put the alfalfa hay within the reach of the horse
2) the rope isn't tied to anything...at least it doesn't say anything about the horse being tied up to anything, or maybe I misread something......

Wait, so if 'no man or woman likes the owner'... then this must have something to do with an animal...?

Pheonix_1 and Witherwings are both on the right track, just combine and change them around a little and you'll have it!

Hmmm....the horse walks towards the hay of alfalfa because the rope is not tied to anything????? or....i don't know....hmmm or an animal accidentally pushes the hay within the reach of the horse (if it is tied up)

um... this is probably wrong but i'll give it a try (even if it has nothing to do with my right track ):

there are two piles of hay, one of them is near the horse...?
im probably wrong, arent i?



ohhhh! maybe-
the hay is on another horse,
and the horse moves... ???
wrong again, right?

*Sigh* You are both wrong. And you're both leading farther away from the point! Come on, I know you can do this!

I haven't figured it out yet- just a few hints to point out.

- no man or women likes the owner
- the owner is drunk
- the owner stays to nights at the bar, forgetting about his horse
- his shirt is red, the rope is red... there's something there.



OHHH
I'm gonna add something:

Maybe the hay is two meters and 3 inches away from the tree, and the horse is five meters away from the tree on the other side, so he could easily turn around and eat the hay if it is only two meters away from the tree... but then again I think this is wrong, considering the obvious hints I posted above... C'mon, give us a hint!

Honestly? The only hints I can give you without giving it away are

1) No man or woman likes the owner
2) Some information is misleading or unimportant
3) Think Think Think! It's really pretty simple...

Maybe the answer is not that complicated like most riddles.

I have an idea but it's too simple...
Like you say, no man or woman likes the owner,
if a person just maybe untied the rope and tied the horse to another red rope
but the owner was too drunk to care?

I know this won't work...but I was thinking hard since the riddle was out, and this is all I got up to

Maybe somebody just moved the hay closer to the horse?
It's not the owner, cause he hasn't seen the horse for two days or whatever it was. And it says that nobody likes the owner or the horse, but perhaps somebody felt sorry for the horse. And maybe the horse was unhappy because he was hungry and made a lot of noise, and that's why poeple didn't like him, so they moved the hay closer

lol rambling i hope i made sense